Syntax:
LastDayOfYear(dateexpr)
Description:
Returns the last day (i.e. Sunday, Monday, etc.) of the year specified
by dateexpr. For
example, this function could return the name of last day of the current
year. The
return integer is one of the following:
ò vbSunday (1) - Sunday
ò vbMonday (2) - Monday
ò vbTuesday (3) - Tuesday
ò vbWednesday (4) - Wednesday
ò vbThursday (5) - Thursday
ò vbFriday (6) - Friday
ò vbSaturday (7) - Saturday
Parameter Description
dateexpr A date which contains the year to be examined
Example:
Sub
Main
'return the name of the last day of this year
lastDayOfTheYear = LastDayOfTheYear (Now())
End Sub
See Also